2x+47=5(x+4)

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Solution for 2x+47=5(x+4) equation: 



2x+47=5(x+4)

We move all terms to the left:

2x+47-(5(x+4))=0



We calculate terms in parentheses: -(5(x+4)), so:

5(x+4)

We multiply parentheses

5x+20

Back to the equation:

-(5x+20)



We get rid of parentheses

2x-5x-20+47=0

We add all the numbers together, and all the variables

-3x+27=0

We move all terms containing x to the left, all other terms to the right

-3x=-27

x=-27/-3

x=+9

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