2x+4(x-8)=3(x-2)+7

Solution for 2x+4(x-8)=3(x-2)+7 equation:

2x+4(x-8)=3(x-2)+7

We move all terms to the left:

2x+4(x-8)-(3(x-2)+7)=0

We multiply parentheses

2x+4x-(3(x-2)+7)-32=0


We calculate terms in parentheses: -(3(x-2)+7), so:

3(x-2)+7

We multiply parentheses

3x-6+7

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)


We add all the numbers together, and all the variables

6x-(3x+1)-32=0

We get rid of parentheses

6x-3x-1-32=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11