2x+4(x-1)=3(2x+3)+x-4

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Solution for 2x+4(x-1)=3(2x+3)+x-4 equation: 



2x+4(x-1)=3(2x+3)+x-4

We move all terms to the left:

2x+4(x-1)-(3(2x+3)+x-4)=0

We multiply parentheses

2x+4x-(3(2x+3)+x-4)-4=0



We calculate terms in parentheses: -(3(2x+3)+x-4), so:

3(2x+3)+x-4

We add all the numbers together, and all the variables

x+3(2x+3)-4

We multiply parentheses

x+6x+9-4

We add all the numbers together, and all the variables

7x+5

Back to the equation:

-(7x+5)



We add all the numbers together, and all the variables

6x-(7x+5)-4=0

We get rid of parentheses

6x-7x-5-4=0

We add all the numbers together, and all the variables

-1x-9=0

We move all terms containing x to the left, all other terms to the right

-x=9

x=9/-1

x=-9

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