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2x+4(2x+3)=5(2x+9)-33
We move all terms to the left:
2x+4(2x+3)-(5(2x+9)-33)=0
We multiply parentheses
2x+8x-(5(2x+9)-33)+12=0
We calculate terms in parentheses: -(5(2x+9)-33), so:We add all the numbers together, and all the variables
5(2x+9)-33
We multiply parentheses
10x+45-33
We add all the numbers together, and all the variables
10x+12
Back to the equation:
-(10x+12)
10x-(10x+12)+12=0
We get rid of parentheses
10x-10x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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