2x+3y=6;y=(-2/3)x+4

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Remember to put linear equations with variables x and y.
for example:
2x+y=8
x+3y=14

Solution for 2x+3y=6;y=(-2/3)x+4 system of equations: 


  • /| 2*x+3*y-6 = 0| y-((-2/3)*x)-4 = 0
  • We try to solve the equation: 2*x+3*y-6 = 0
  • 2*x+3*y-6 = 0 // - 2*x-6
  • 3*y = -(2*x-6) // : 3
  • y = (-(2*x-6))/3
  • y = (6-(2*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (6-(2*x))/3-((-2/3)*x)-4 = 0| y = (6-(2*x))/3
  • (6-2*x)/3+(2*x)/3-4 = 0
  • 2-4 = 0
  • -2 = 0
  • -2 = 0
  • x belongs to the empty set
  • The system of equations does not have any solution

 

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