2x+3y=3;x+2y=1

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2x+y=8
x+3y=14

Solution for 2x+3y=3;x+2y=1 system of equations: 


  • /| 2*x+3*y-3 = 0| x+2*y-1 = 0
  • We try to solve the equation: 2*x+3*y-3 = 0
  • 2*x+3*y-3 = 0 // - 2*x-3
  • 3*y = -(2*x-3) // : 3
  • y = (-(2*x-3))/3
  • y = (3-(2*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*((3-(2*x))/3)+x-1 = 0| y = (3-(2*x))/3
  • (2*(3-2*x))/3+x-1 = 0
  • 2-1/3*x-1 = 0
  • 1-1/3*x = 0
  • 1-1/3*x = 0 // - 1
  • -1/3*x = -1 // : -1/3
  • x = -1/(-1/3)
  • x = 3
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (3-(2*x))/3: 
  • y = (3-(2*3))/3
  • y = (3-6)/3
  • y = -3/3
  • y = -1
  • We get a system of equations:
  • /| y = -1| x = 3

 

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