2x+3x+10-2+3x+2=56

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Solution for 2x+3x+10-2+3x+2=56 equation: 



2x+3x+10-2+3x+2=56

We move all terms to the left:

2x+3x+10-2+3x+2-(56)=0

We add all the numbers together, and all the variables

8x-46=0

We move all terms containing x to the left, all other terms to the right

8x=46

x=46/8

x=5+3/4

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