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2x+3x+(x-12)=2x+3x+(x-12)
We move all terms to the left:
2x+3x+(x-12)-(2x+3x+(x-12))=0
We add all the numbers together, and all the variables
5x+(x-12)-(2x+3x+(x-12))=0
We get rid of parentheses
5x+x-(2x+3x+(x-12))-12=0
We calculate terms in parentheses: -(2x+3x+(x-12)), so:We add all the numbers together, and all the variables
2x+3x+(x-12)
We add all the numbers together, and all the variables
5x+(x-12)
We get rid of parentheses
5x+x-12
We add all the numbers together, and all the variables
6x-12
Back to the equation:
-(6x-12)
6x-(6x-12)-12=0
We get rid of parentheses
6x-6x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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