2x+36=(4/11)x

Solution for 2x+36=(4/11)x equation:

2x+36=(4/11)x

We move all terms to the left:

2x+36-((4/11)x)=0


Domain of the equation: 11)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-((+4/11)x)+36=0

We multiply all the terms by the denominator


2x*11)x)-((+36*11)x)+4=0

We add all the numbers together, and all the variables

2x*11)x)-(396x)+4=0

We add all the numbers together, and all the variables

2x*11)x)-396x+4=0

Wy multiply elements

22x^2=0

a = 22; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·22·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{44}=0$