2x+35=4/11x

Solution for 2x+35=4/11x equation:

2x+35=4/11x

We move all terms to the left:

2x+35-(4/11x)=0


Domain of the equation: 11x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(+4/11x)+35=0

We get rid of parentheses

2x-4/11x+35=0

We multiply all the terms by the denominator


2x*11x+35*11x-4=0

Wy multiply elements

22x^2+385x-4=0

a = 22; b = 385; c = -4;
Δ = b2-4ac
Δ = 3852-4·22·(-4)
Δ = 148577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(385)-\sqrt{148577}}{2*22}=\frac{-385-\sqrt{148577}}{44}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(385)+\sqrt{148577}}{2*22}=\frac{-385+\sqrt{148577}}{44}
$