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2x+35=3(x+5)
We move all terms to the left:
2x+35-(3(x+5))=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
2x-3x-15+35=0
We add all the numbers together, and all the variables
-1x+20=0
We move all terms containing x to the left, all other terms to the right
-x=-20
x=-20/-1
x=+20
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