2x+33=-7(1-6x)

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Solution for 2x+33=-7(1-6x) equation: 



2x+33=-7(1-6x)

We move all terms to the left:

2x+33-(-7(1-6x))=0

We add all the numbers together, and all the variables

2x-(-7(-6x+1))+33=0



We calculate terms in parentheses: -(-7(-6x+1)), so:

-7(-6x+1)

We multiply parentheses

42x-7

Back to the equation:

-(42x-7)



We get rid of parentheses

2x-42x+7+33=0

We add all the numbers together, and all the variables

-40x+40=0

We move all terms containing x to the left, all other terms to the right

-40x=-40

x=-40/-40

x=1

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