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2x+3/x=-35
We move all terms to the left:
2x+3/x-(-35)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
2x+3/x+35=0
We multiply all the terms by the denominator
2x*x+35*x+3=0
We add all the numbers together, and all the variables
35x+2x*x+3=0
Wy multiply elements
2x^2+35x+3=0
a = 2; b = 35; c = +3;
Δ = b2-4ac
Δ = 352-4·2·3
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1201}}{2*2}=\frac{-35-\sqrt{1201}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1201}}{2*2}=\frac{-35+\sqrt{1201}}{4} $
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