2x+3-4x=H4(x-5)

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Solution for 2x+3-4x=H4(x-5) equation: 



2x+3-4x=4(x-5)

We move all terms to the left:

2x+3-4x-(4(x-5))=0

We add all the numbers together, and all the variables

-2x-(4(x-5))+3=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We get rid of parentheses

-2x-4x+20+3=0

We add all the numbers together, and all the variables

-6x+23=0

We move all terms containing x to the left, all other terms to the right

-6x=-23

x=-23/-6

x=3+5/6

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