2x+3-4(x+1)=6x-2(x-5)

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Solution for 2x+3-4(x+1)=6x-2(x-5) equation: 



2x+3-4(x+1)=6x-2(x-5)

We move all terms to the left:

2x+3-4(x+1)-(6x-2(x-5))=0

We multiply parentheses

2x-4x-(6x-2(x-5))-4+3=0



We calculate terms in parentheses: -(6x-2(x-5)), so:

6x-2(x-5)

We multiply parentheses

6x-2x+10

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We add all the numbers together, and all the variables

-2x-(4x+10)-1=0

We get rid of parentheses

-2x-4x-10-1=0

We add all the numbers together, and all the variables

-6x-11=0

We move all terms containing x to the left, all other terms to the right

-6x=11

x=11/-6

x=-1+5/6

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