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2x+3*1/2x=105
We move all terms to the left:
2x+3*1/2x-(105)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
2x*2x-105*2x+3*1=0
We add all the numbers together, and all the variables
2x*2x-105*2x+3=0
Wy multiply elements
4x^2-210x+3=0
a = 4; b = -210; c = +3;
Δ = b2-4ac
Δ = -2102-4·4·3
Δ = 44052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44052}=\sqrt{4*11013}=\sqrt{4}*\sqrt{11013}=2\sqrt{11013}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-210)-2\sqrt{11013}}{2*4}=\frac{210-2\sqrt{11013}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-210)+2\sqrt{11013}}{2*4}=\frac{210+2\sqrt{11013}}{8} $
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