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2x+3(x-6)=2(x-3)
We move all terms to the left:
2x+3(x-6)-(2(x-3))=0
We multiply parentheses
2x+3x-(2(x-3))-18=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
5x-(2x-6)-18=0
We get rid of parentheses
5x-2x+6-18=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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