2x+3(x-1)=7x+1-2(x+2)

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Solution for 2x+3(x-1)=7x+1-2(x+2) equation: 



2x+3(x-1)=7x+1-2(x+2)

We move all terms to the left:

2x+3(x-1)-(7x+1-2(x+2))=0

We multiply parentheses

2x+3x-(7x+1-2(x+2))-3=0



We calculate terms in parentheses: -(7x+1-2(x+2)), so:

7x+1-2(x+2)

determiningTheFunctionDomain
7x-2(x+2)+1

We multiply parentheses

7x-2x-4+1

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We add all the numbers together, and all the variables

5x-(5x-3)-3=0

We get rid of parentheses

5x-5x+3-3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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