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2x+3(x-1)=6(x-1)-x
We move all terms to the left:
2x+3(x-1)-(6(x-1)-x)=0
We multiply parentheses
2x+3x-(6(x-1)-x)-3=0
We calculate terms in parentheses: -(6(x-1)-x), so:We add all the numbers together, and all the variables
6(x-1)-x
We add all the numbers together, and all the variables
-1x+6(x-1)
We multiply parentheses
-1x+6x-6
We add all the numbers together, and all the variables
5x-6
Back to the equation:
-(5x-6)
5x-(5x-6)-3=0
We get rid of parentheses
5x-5x+6-3=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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