2x+2=4/9x

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Solution for 2x+2=4/9x equation:



2x+2=4/9x
We move all terms to the left:
2x+2-(4/9x)=0
Domain of the equation: 9x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
2x-(+4/9x)+2=0
We get rid of parentheses
2x-4/9x+2=0
We multiply all the terms by the denominator
2x*9x+2*9x-4=0
Wy multiply elements
18x^2+18x-4=0
a = 18; b = 18; c = -4;
Δ = b2-4ac
Δ = 182-4·18·(-4)
Δ = 612
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{612}=\sqrt{36*17}=\sqrt{36}*\sqrt{17}=6\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{17}}{2*18}=\frac{-18-6\sqrt{17}}{36} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{17}}{2*18}=\frac{-18+6\sqrt{17}}{36} $

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