2x+22=4(4x+3)

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Solution for 2x+22=4(4x+3) equation: 



2x+22=4(4x+3)

We move all terms to the left:

2x+22-(4(4x+3))=0



We calculate terms in parentheses: -(4(4x+3)), so:

4(4x+3)

We multiply parentheses

16x+12

Back to the equation:

-(16x+12)



We get rid of parentheses

2x-16x-12+22=0

We add all the numbers together, and all the variables

-14x+10=0

We move all terms containing x to the left, all other terms to the right

-14x=-10

x=-10/-14

x=5/7

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