2x+20=x+6012)4x+1=25+2x

Solution for 2x+20=x+6012)4x+1=25+2x equation:

2x+20=x+6012)4x+1=25+2x

We move all terms to the left:

2x+20-(x+6012)4x+1)=0

We add all the numbers together, and all the variables

2x-(x+6012)4x=0

We multiply parentheses

-4x^2+2x-24048x=0

We add all the numbers together, and all the variables

-4x^2-24046x=0

a = -4; b = -24046; c = 0;
Δ = b2-4ac
Δ = -240462-4·(-4)·0
Δ = 578210116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{578210116}=24046$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24046)-24046}{2*-4}=\frac{0}{-8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24046)+24046}{2*-4}=\frac{48092}{-8}
=-6011+1/2
$