2x+2(x-1)=3(x-4)

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Solution for 2x+2(x-1)=3(x-4) equation: 



2x+2(x-1)=3(x-4)

We move all terms to the left:

2x+2(x-1)-(3(x-4))=0

We multiply parentheses

2x+2x-(3(x-4))-2=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

4x-(3x-12)-2=0

We get rid of parentheses

4x-3x+12-2=0

We add all the numbers together, and all the variables

x+10=0

We move all terms containing x to the left, all other terms to the right

x=-10

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