2x+2(x+5)=(x+7)+(x+4)+(x+11)

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Solution for 2x+2(x+5)=(x+7)+(x+4)+(x+11) equation: 



2x+2(x+5)=(x+7)+(x+4)+(x+11)

We move all terms to the left:

2x+2(x+5)-((x+7)+(x+4)+(x+11))=0

We multiply parentheses

2x+2x-((x+7)+(x+4)+(x+11))+10=0



We calculate terms in parentheses: -((x+7)+(x+4)+(x+11)), so:

(x+7)+(x+4)+(x+11)

We get rid of parentheses

x+x+x+7+4+11

We add all the numbers together, and all the variables

3x+22

Back to the equation:

-(3x+22)



We add all the numbers together, and all the variables

4x-(3x+22)+10=0

We get rid of parentheses

4x-3x-22+10=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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