2x+2(3x-1)=3(x+1)

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Solution for 2x+2(3x-1)=3(x+1) equation:



2x+2(3x-1)=3(x+1)
We move all terms to the left:
2x+2(3x-1)-(3(x+1))=0
We multiply parentheses
2x+6x-(3(x+1))-2=0
We calculate terms in parentheses: -(3(x+1)), so:
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
We add all the numbers together, and all the variables
8x-(3x+3)-2=0
We get rid of parentheses
8x-3x-3-2=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1

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