2x+1=5-3(x-2)

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Solution for 2x+1=5-3(x-2) equation: 



2x+1=5-3(x-2)

We move all terms to the left:

2x+1-(5-3(x-2))=0



We calculate terms in parentheses: -(5-3(x-2)), so:

5-3(x-2)

determiningTheFunctionDomain
-3(x-2)+5

We multiply parentheses

-3x+6+5

We add all the numbers together, and all the variables

-3x+11

Back to the equation:

-(-3x+11)



We get rid of parentheses

2x+3x-11+1=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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