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2x+11=9x/3
We move all terms to the left:
2x+11-(9x/3)=0
We add all the numbers together, and all the variables
2x-(+9x/3)+11=0
We get rid of parentheses
2x-9x/3+11=0
We multiply all the terms by the denominator
2x*3-9x+11*3=0
We add all the numbers together, and all the variables
-9x+2x*3+33=0
Wy multiply elements
-9x+6x+33=0
We add all the numbers together, and all the variables
-3x+33=0
We move all terms containing x to the left, all other terms to the right
-3x=-33
x=-33/-3
x=+11
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