2x+10x-8=40-4x

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Solution for 2x+10x-8=40-4x equation: 



2x+10x-8=40-4x

We move all terms to the left:

2x+10x-8-(40-4x)=0

We add all the numbers together, and all the variables

2x+10x-(-4x+40)-8=0

We add all the numbers together, and all the variables

12x-(-4x+40)-8=0

We get rid of parentheses

12x+4x-40-8=0

We add all the numbers together, and all the variables

16x-48=0

We move all terms containing x to the left, all other terms to the right

16x=48

x=48/16

x=3

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