2x+10+12-5x=1/2(-6x+22)+11

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Solution for 2x+10+12-5x=1/2(-6x+22)+11 equation: 



2x+10+12-5x=1/2(-6x+22)+11

We move all terms to the left:

2x+10+12-5x-(1/2(-6x+22)+11)=0



Domain of the equation: 2(-6x+22)+11)!=0

x∈R



We add all the numbers together, and all the variables

-3x-(1/2(-6x+22)+11)+22=0

We multiply all the terms by the denominator


-3x*2(-6x+22)+22*2(-6x+22)+11)-(1+11)=0

We add all the numbers together, and all the variables

-3x*2(-6x+22)+22*2(-6x+22)+11)-12=0

We add all the numbers together, and all the variables

-3x*2(-6x+22)+22*2(-6x+22)=0

Wy multiply elements

-6x^2(-+44x(-=0

We use the square of the difference formula

-6x^2(-44x(-=0

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