2x+1/2x=54

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Solution for 2x+1/2x=54 equation:



2x+1/2x=54
We move all terms to the left:
2x+1/2x-(54)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We multiply all the terms by the denominator
2x*2x-54*2x+1=0
Wy multiply elements
4x^2-108x+1=0
a = 4; b = -108; c = +1;
Δ = b2-4ac
Δ = -1082-4·4·1
Δ = 11648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{11648}=\sqrt{64*182}=\sqrt{64}*\sqrt{182}=8\sqrt{182}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-8\sqrt{182}}{2*4}=\frac{108-8\sqrt{182}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+8\sqrt{182}}{2*4}=\frac{108+8\sqrt{182}}{8} $

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