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2x+1/2x=50
We move all terms to the left:
2x+1/2x-(50)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
2x*2x-50*2x+1=0
Wy multiply elements
4x^2-100x+1=0
a = 4; b = -100; c = +1;
Δ = b2-4ac
Δ = -1002-4·4·1
Δ = 9984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9984}=\sqrt{256*39}=\sqrt{256}*\sqrt{39}=16\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-16\sqrt{39}}{2*4}=\frac{100-16\sqrt{39}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+16\sqrt{39}}{2*4}=\frac{100+16\sqrt{39}}{8} $
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