2x+(x-8)=7(4+x)+8x

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Solution for 2x+(x-8)=7(4+x)+8x equation: 



2x+(x-8)=7(4+x)+8x

We move all terms to the left:

2x+(x-8)-(7(4+x)+8x)=0

We add all the numbers together, and all the variables

2x+(x-8)-(7(x+4)+8x)=0

We get rid of parentheses

2x+x-(7(x+4)+8x)-8=0



We calculate terms in parentheses: -(7(x+4)+8x), so:

7(x+4)+8x

We add all the numbers together, and all the variables

8x+7(x+4)

We multiply parentheses

8x+7x+28

We add all the numbers together, and all the variables

15x+28

Back to the equation:

-(15x+28)



We add all the numbers together, and all the variables

3x-(15x+28)-8=0

We get rid of parentheses

3x-15x-28-8=0

We add all the numbers together, and all the variables

-12x-36=0

We move all terms containing x to the left, all other terms to the right

-12x=36

x=36/-12

x=-3

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