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2x+(x-2)=4x-(x-3)
We move all terms to the left:
2x+(x-2)-(4x-(x-3))=0
We get rid of parentheses
2x+x-(4x-(x-3))-2=0
We calculate terms in parentheses: -(4x-(x-3)), so:We add all the numbers together, and all the variables
4x-(x-3)
We get rid of parentheses
4x-x+3
We add all the numbers together, and all the variables
3x+3
Back to the equation:
-(3x+3)
3x-(3x+3)-2=0
We get rid of parentheses
3x-3x-3-2=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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