2x+(5/x)=2

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Solution for 2x+(5/x)=2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+5/x = 2 // - 2

2*x+5/x-2 = 0

2*x^1+5*x^-1-2*x^0 = 0

(2*x^2-2*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-2*x^1+5*x^0) = 0

x^1

2*x^2-2*x+5 = 0

2*x^2-2*x+5 = 0

DELTA = (-2)^2-(2*4*5)

DELTA = -36

DELTA < 0

x in { } 

x belongs to the empty set

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