2x+(3x-4)=16

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Solution for 2x+(3x-4)=16 equation: 



2x+(3x-4)=16

We move all terms to the left:

2x+(3x-4)-(16)=0

We get rid of parentheses

2x+3x-4-16=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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