2x+(2x/3)=3328

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Solution for 2x+(2x/3)=3328 equation:



2x+(2x/3)=3328
We move all terms to the left:
2x+(2x/3)-(3328)=0
We add all the numbers together, and all the variables
2x+(+2x/3)-3328=0
We get rid of parentheses
2x+2x/3-3328=0
We multiply all the terms by the denominator
2x*3+2x-3328*3=0
We add all the numbers together, and all the variables
2x+2x*3-9984=0
Wy multiply elements
2x+6x-9984=0
We add all the numbers together, and all the variables
8x-9984=0
We move all terms containing x to the left, all other terms to the right
8x=9984
x=9984/8
x=1248

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