2x*3x=5+36x=0

Solution for 2x*3x=5+36x=0 equation:

2x*3x=5+36x=0

We move all terms to the left:

2x*3x-(5+36x)=0

We add all the numbers together, and all the variables

2x*3x-(36x+5)=0

Wy multiply elements

6x^2-(36x+5)=0

We get rid of parentheses

6x^2-36x-5=0

a = 6; b = -36; c = -5;
Δ = b2-4ac
Δ = -362-4·6·(-5)
Δ = 1416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1416}=\sqrt{4*354}=\sqrt{4}*\sqrt{354}=2\sqrt{354}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-2\sqrt{354}}{2*6}=\frac{36-2\sqrt{354}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+2\sqrt{354}}{2*6}=\frac{36+2\sqrt{354}}{12}
$