2x*2x=2x-3*x+10

Solution for 2x*2x=2x-3*x+10 equation:

2x*2x=2x-3x+10

We move all terms to the left:

2x*2x-(2x-3x+10)=0

We add all the numbers together, and all the variables

2x*2x-(-1x+10)=0

Wy multiply elements

4x^2-(-1x+10)=0

We get rid of parentheses

4x^2+1x-10=0

We add all the numbers together, and all the variables

4x^2+x-10=0

a = 4; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·4·(-10)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{161}}{2*4}=\frac{-1-\sqrt{161}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{161}}{2*4}=\frac{-1+\sqrt{161}}{8}
$