2x*(1-7x)=0

Solution for 2x*(1-7x)=0 equation:

2x(1-7x)=0

We add all the numbers together, and all the variables

2x(-7x+1)=0

We multiply parentheses

-14x^2+2x=0

a = -14; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-14)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-14}=\frac{-4}{-28}
=1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-14}=\frac{0}{-28}
=0
$