2x(x-4)=2x2-8x

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Solution for 2x(x-4)=2x2-8x equation: 



2x(x-4)=2x^2-8x

We move all terms to the left:

2x(x-4)-(2x^2-8x)=0

We multiply parentheses

2x^2-8x-(2x^2-8x)=0

We get rid of parentheses

2x^2-2x^2-8x+8x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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