2x(x-3)=x(2x+4-80)

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Solution for 2x(x-3)=x(2x+4-80) equation: 



2x(x-3)=x(2x+4-80)

We move all terms to the left:

2x(x-3)-(x(2x+4-80))=0

We add all the numbers together, and all the variables

2x(x-3)-(x(2x-76))=0

We multiply parentheses

2x^2-6x-(x(2x-76))=0



We calculate terms in parentheses: -(x(2x-76)), so:

x(2x-76)

We multiply parentheses

2x^2-76x

Back to the equation:

-(2x^2-76x)



We get rid of parentheses

2x^2-2x^2-6x+76x=0

We add all the numbers together, and all the variables

70x=0

x=0/70

x=0

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