2x(x-3)=2x2+3x+72

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Solution for 2x(x-3)=2x2+3x+72 equation:



2x(x-3)=2x^2+3x+72
We move all terms to the left:
2x(x-3)-(2x^2+3x+72)=0
We multiply parentheses
2x^2-6x-(2x^2+3x+72)=0
We get rid of parentheses
2x^2-2x^2-6x-3x-72=0
We add all the numbers together, and all the variables
-9x-72=0
We move all terms containing x to the left, all other terms to the right
-9x=72
x=72/-9
x=-8

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