2x(x-3)=(2x+4)-80

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Solution for 2x(x-3)=(2x+4)-80 equation:



2x(x-3)=(2x+4)-80
We move all terms to the left:
2x(x-3)-((2x+4)-80)=0
We multiply parentheses
2x^2-6x-((2x+4)-80)=0
We calculate terms in parentheses: -((2x+4)-80), so:
(2x+4)-80
We get rid of parentheses
2x+4-80
We add all the numbers together, and all the variables
2x-76
Back to the equation:
-(2x-76)
We get rid of parentheses
2x^2-6x-2x+76=0
We add all the numbers together, and all the variables
2x^2-8x+76=0
a = 2; b = -8; c = +76;
Δ = b2-4ac
Δ = -82-4·2·76
Δ = -544
Delta is less than zero, so there is no solution for the equation

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