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2x(x-1)=x+18
We move all terms to the left:
2x(x-1)-(x+18)=0
We multiply parentheses
2x^2-2x-(x+18)=0
We get rid of parentheses
2x^2-2x-x-18=0
We add all the numbers together, and all the variables
2x^2-3x-18=0
a = 2; b = -3; c = -18;
Δ = b2-4ac
Δ = -32-4·2·(-18)
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{17}}{2*2}=\frac{3-3\sqrt{17}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{17}}{2*2}=\frac{3+3\sqrt{17}}{4} $
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