2x(x-1)=(2x-5)(x-1)

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Solution for 2x(x-1)=(2x-5)(x-1) equation: 



2x(x-1)=(2x-5)(x-1)

We move all terms to the left:

2x(x-1)-((2x-5)(x-1))=0

We multiply parentheses

2x^2-2x-((2x-5)(x-1))=0

We multiply parentheses ..

2x^2-((+2x^2-2x-5x+5))-2x=0



We calculate terms in parentheses: -((+2x^2-2x-5x+5)), so:

(+2x^2-2x-5x+5)

We get rid of parentheses

2x^2-2x-5x+5

We add all the numbers together, and all the variables

2x^2-7x+5

Back to the equation:

-(2x^2-7x+5)



We add all the numbers together, and all the variables

2x^2-2x-(2x^2-7x+5)=0

We get rid of parentheses

2x^2-2x^2-2x+7x-5=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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