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2x(x+7)=126
We move all terms to the left:
2x(x+7)-(126)=0
We multiply parentheses
2x^2+14x-126=0
a = 2; b = 14; c = -126;
Δ = b2-4ac
Δ = 142-4·2·(-126)
Δ = 1204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1204}=\sqrt{4*301}=\sqrt{4}*\sqrt{301}=2\sqrt{301}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{301}}{2*2}=\frac{-14-2\sqrt{301}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{301}}{2*2}=\frac{-14+2\sqrt{301}}{4} $
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