2x(x+4)=7x+5x-22

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Solution for 2x(x+4)=7x+5x-22 equation: 



2x(x+4)=7x+5x-22

We move all terms to the left:

2x(x+4)-(7x+5x-22)=0

We add all the numbers together, and all the variables

2x(x+4)-(12x-22)=0

We multiply parentheses

2x^2+8x-(12x-22)=0

We get rid of parentheses

2x^2+8x-12x+22=0

We add all the numbers together, and all the variables

2x^2-4x+22=0

a = 2; b = -4; c = +22;
Δ = b2-4ac
Δ = -42-4·2·22
Δ = -160
Delta is less than zero, so there is no solution for the equation

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