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2x(x+4)=3x+15
We move all terms to the left:
2x(x+4)-(3x+15)=0
We multiply parentheses
2x^2+8x-(3x+15)=0
We get rid of parentheses
2x^2+8x-3x-15=0
We add all the numbers together, and all the variables
2x^2+5x-15=0
a = 2; b = 5; c = -15;
Δ = b2-4ac
Δ = 52-4·2·(-15)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{145}}{2*2}=\frac{-5-\sqrt{145}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{145}}{2*2}=\frac{-5+\sqrt{145}}{4} $
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