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2x(x+30)=330
We move all terms to the left:
2x(x+30)-(330)=0
We multiply parentheses
2x^2+60x-330=0
a = 2; b = 60; c = -330;
Δ = b2-4ac
Δ = 602-4·2·(-330)
Δ = 6240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6240}=\sqrt{16*390}=\sqrt{16}*\sqrt{390}=4\sqrt{390}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{390}}{2*2}=\frac{-60-4\sqrt{390}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{390}}{2*2}=\frac{-60+4\sqrt{390}}{4} $
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