2x(x+3)=3(x-4)

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Solution for 2x(x+3)=3(x-4) equation: 



2x(x+3)=3(x-4)

We move all terms to the left:

2x(x+3)-(3(x-4))=0

We multiply parentheses

2x^2+6x-(3(x-4))=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

2x^2+6x-3x+12=0

We add all the numbers together, and all the variables

2x^2+3x+12=0

a = 2; b = 3; c = +12;
Δ = b2-4ac
Δ = 32-4·2·12
Δ = -87
Delta is less than zero, so there is no solution for the equation

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